You can dissolve an aluminum soft drink can in an aqueous base such as potassium hydroxide. If

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You can dissolve an aluminum soft drink can in an aqueous base such as potassium hydroxide. 2 Al(s) + 2 KOH(aq) + 6 HO(l) 2 KAl(OH)4 (aq) + 3 H(g)

If you place 2.05 g of aluminum in a beaker with 185 mL of 1.35 M KOH, will any aluminum remain? What mass of KAl(OH)₄ is produced?

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Chemistry And Chemical Reactivity

ISBN: 9780357001172

10th Edition

Authors: John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

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Question Posted: Oct 16, 2023 03:41 AM

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You can dissolve an aluminum soft drink can in an aqueous base such as potassium hydroxide. If

Question:

2 Al(s) + 2 KOH(aq) + 6 H₂O(l) → 2 KAl(OH)4 (aq) + 3 H₂(g)

Step by Step Answer:

To determine whether any aluminum remains and to calculate the mass of KAlOH4 produced we can use st...View the full answer

Chemistry And Chemical Reactivity

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