A reaction rate doubles when an investigator increases the temperature by 10 C, from 298 to 308

Question:

A reaction rate doubles when an investigator increases the temperature by 10 °C, from 298 to 308 K . What is the activation energy?

Strategy

Start with Equation 13.11:

To solve this problem, we need to recognize that the ratio k₁/k₂ is 1:2 because we are told that the rate doubles. Because we are given T₁ and T₂, and R is a constant that we know, we can solve for the activation energy, Ea.

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Step by Step Answer:

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Chemistry Principles And Practice

ISBN: 9780534420123

3rd Edition

Authors: Daniel L. Reger, Scott R. Goode, David W. Ball

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Question Posted: Jan 04, 2024 11:41 AM

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A reaction rate doubles when an investigator increases the temperature by 10 C, from 298 to 308

Question:

-E. (1 1n (4/2) = R - ( 12/12 In k RT 1 T

Step by Step Answer:

Let T be 298 and 7 be 308 K The ratio of the ...View the full answer

Chemistry Principles And Practice

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