At 298 K, the solubility product constant for Pb(IO 3 ) 2 is 2.6 10 -13

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At 298 K, the solubility product constant for Pb(IO3)2

is 2.6 × 10-13, and the standard reduction potential of the Pb2+ (aq) to Pb(s) is -0.126 V.

(a) Find the standard potential of the half-reactionPb(IO3)2(s) + 2e Pb(s) + 2103 (aq)

The desired half-reaction is the sum of the equations for the solubility product and the reduction of Pb2+. Find ΔG° for these two reactions, and add them to find ΔG° for their sum. Convert the ΔG° to the potential of the desired half-reaction.)

(b) Calculate the potential of the Pb/Pb(IO3)2 electrode in a 3.5 × 10-3 M solution of NaIO3.

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Related Book For  book-img-for-question

Chemistry Principles And Practice

ISBN: 9780534420123

3rd Edition

Authors: Daniel L. Reger, Scott R. Goode, David W. Ball

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