Calculate the energy released in the following spontaneous fission reaction: Strategy As always, the energy released is

Question:

Calculate the energy released in the following spontaneous fission reaction:238 SU 95 Sr+ 140 Xe + 3n 32.26

given the atomic masses to be m(238 U)= 238.050784 u, m(95 Sr)= 94.919388 u, m(140 Xe)= 139.921610 u, and

Strategy

As always, the energy released is equal to the mass destroyed times c2, so we must find the difference in mass between the parent 238U and the fission products.

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