Suppose the train in Figure 2.18(a) accelerates from rest to 30.0 km/h in the first 20.0 s

Question:

Suppose the train in Figure 2.18(a) accelerates from rest to 30.0 km/h in the first 20.0 s of its motion. What is its average acceleration during that time interval?

Data given in Figure 2.18

y 0 (b) Ax 2.00 km x = 3.75 km 1x0 = 4.70 km Ax' = -1.50 km x6 = 5.25 km xf = 6.70 km x (km) -x (km)

Strategy

 
It is worth it at this point to make a simple sketch:

20 = 0 km/h V = 30.0 km/h a = ? y x


This problem involves three steps. First we must determine the change in velocity, then we must determine the change in time, and finally we use these values to calculate the acceleration.

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