Suppose a golf ball is hit off the tee with an initial velocity of 30.0 m/s at an angle of 35° to the horizontal, as in Figure 3.12. (a) What is the maximum height reached by the ball? (b) What is its range? 
THINKING IT THROUGH. The maximum height involves the y-component; the procedure for finding this is like that for finding the maximum height of a ball projected vertically upward. The ball travels in the x-direction for the same amount of time it would take for the ball to go up and down.

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Ymax= Vy2 Vy3 = 0 050 DYA Oxo Dyo Range R=Xx max 1 www Vy6 0x0 x FIGURE 3.12 Projection at an angle The velocity components of the ball are shown for various times. Note that v,=0 at the top of the arc, or at ymax The range R is the maximum horizontal distance, or xmax (Notice that v=v in magnitude. Why?)