To walk 1000 m on level ground, a 60-kg person requires an expenditure of about 1.0 × 105 J of energy. What is the total energy required if the walk is extended another 1000 m along a 5.0° incline as shown in ▼ Figure 5.16? (Neglect any frictional changes.)
THINKING IT THROUGH. To walk an additional 1000 m would require another 1.0 × 105 J plus the additional energy for doing work against gravity in walking up the incline. From the figure, the increase in height can be seen to be h = d sin θ, where d is 1000 m.

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T -1000 m- -1000 m- FIGURE 5.16 Adding potential energy See Example 5.8 for description.