A proton is directed such that it comes within 1.8 10 -15 m of a carbon

Question:

A proton is directed such that it comes within 1.8 × 10-15 m of a carbon nucleus. 

(a) How much kinetic energy must the proton have initially to get this close to (i.e., “collide” with) the carbon nucleus? 

(b) What is the corresponding speed of the proton? 

(c) What potential would be needed to give the proton this much kinetic energy? Assume the target carbon nucleus is completely ionized (missing all electrons), and that the collision is head-on.

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