The equatorial circumference of Earth is approximately \(4.007 \times 10^{4} \mathrm{~km}\). Use the answer from Exercise 52 to determine the number of times that the stretched out human DNA would encircle Earth.

Apply your understanding of scientific notation to real-world applications.

Data from Exercises 52

One approximation of the average number of cells in the human body is \(3 \times 10^{13}\) cells ( 30 trillion!!!). If the DNA of each cell were stretched out and laid end to end, what would be the total length of the DNA in km? Use your answer from Exercise 51 for the length, in kilometers, of DNA.

Data from Exercises 51.

When stretched out, a strand of human DNA is, on average, \(2.066 \times 10^{2} \mathrm{~cm}\). One centimeter, or \(1 \mathrm{~cm}\), is \(1 \times 10^{-5} \mathrm{~km}\). Determine the average length of a strand of human DNA in kilometers.