Given that x 2 + 10x + 36 (x + a) 2 + b, where a and
Question:
Given that x2 + 10x + 36 (x + a)2 + b, where a and b are constants,
a. Find the value of a and the value of b.
b. Hence show that the equation x2 + 10x + 36 = 0 has no real roots. The equation x2 + 10x + k = 0 has equal roots.
c. Find the value of k.
d. For this value of k, sketch the graph of y = x2 + 10x + k, showing the coordinates of any points at which the graph meets the coordinate axes.
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a To find the values of a and b we can expand the given expression x2 10x 36x a2 b x2 10x 36x2 2ax a...View the full answer
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Related Book For
Edexcel AS And A Level Mathematics Pure Mathematics Year 1/AS
ISBN: 9781292183398
1st Edition
Authors: Greg Attwood
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