In light of Exercise 2.14 , the compatibility equations (2.6.2) can be expressed as n ij =

Question:

In light of Exercise 2.14 , the compatibility equations (2.6.2) can be expressed as nij = εikl εjmpelp,km = 0, where nij is sometimes referred to as the incompatibility tensor (Asaro and Lubarda, 2006). It is observed that hij is symmetric, but its components are not independent from one another. Since the divergence of a curl vanishes, show that they are related through the differential Bianchi relations nij,j = 0, which can be expanded to:

M11,1 + 12,2 + 713,3 = 0 721,1 + 122,2 + 123,3 = 0 131,1 + 132,2+ 133,3 = 0

Thus, we see again that the six compatibility relations are not all independent.

Data from exercise 2.14

Using relation (1.3.5), show that the compatibility relations (2.6.1) with l = k can be expressed by ŋij = εiklεjmpelp,km = 0, which can also be written in vector notation as ∇ × e × ∇ = 0.

Equation 1.3.5

Eijk Epqr dip dig dir Sir djr Sjp Sjg Skp Skg Skr

Equation 2.6.1

eij kleklijeik, jl - ejl, ik = 0

Equation 2.6.2

2ex, Pey  dx Pey, Pez + az2  Pez Pex + x az2  2ex z  aey z || aexy = 2-  ( -    - Feyz z 2- 2 aezx z   de yz

Fantastic news! We've Found the answer you've been seeking!

Step by Step Answer:

Related Book For  book-img-for-question
Question Posted: