[15] We compare M(x) and Mc(x). Show that for some infinite (such as a computable real) we have limn M(1:n)/Mc(1:n) = . Comments. Hint:

[15] We compare M(x) and Mc(x). Show that for some infinite

ω (such as a computable real) we have limn→∞ M(ω1:n)/Mc(ω1:n) = ∞.

Comments. Hint: Since 0.ω is a computable real, limn→∞ M(ω1:n) > 0.