Question: Note that (2.14) gives rise to a mass function satisfying (2.6) since, by the binomial theorem, Xn k=0 n k pkqnk = (p

Note that (2.14) gives rise to a mass function satisfying (2.6) since, by the binomial theorem, Xn k=0



n k



pkqn−k = (p + q)n = 1.

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