Using the difference equation V n = V n1 + V n+1 with V o = V

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Using the difference equation V= Vn–1 + Vn+1 with Vo =  V= 1 and starting with initial values Vn = 0 for 1 ≤ n ≤ 4, the value of V2 after the third iteration is

(a) 1  
(b) 3

(c) 9 

(d) 15

(e) 25


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