A tank has a hole in the bottom with a cross-sectional area of 0.0025 m² and an inlet line on the side with a cross-sectional area of 0.0025 m², as shown. The cross-sectional area of the tank is 0.1 m². The velocity of the liquid flowing out the bottom hole is V = √2gh, where h is the height of the water surface in the tank above the outlet. At a certain time, the surface level in the tank is 1 m and rising at the rate of 0.1 cm/s. The liquid is incompressible. Find the velocity of the liquid through the inlet.

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A = 0.1 m? h=1m V. =? in A = 0.0025 m? A = 0.0025 m2 V = V2gh