The 20-kg block is subjected to the action of the harmonic force F = (90 cos 6t)

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The 20-kg block is subjected to the action of the harmonic force F = (90 cos 6t) N, where t is in seconds. Write the equation which describes the steady-state motion.

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Engineering Mechanics Statics & Dynamics

ISBN: 9780134895154

15th Edition

Authors: Russell C. Hibbeler

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Question Posted: Feb 14, 2023 02:42 AM

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The 20-kg block is subjected to the action of the harmonic force F = (90 cos 6t)

Question:

k = 400 N/m 50000 W k = 400 N/m 20 kg F = 90 cos 6t D c=125 N s/m

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From Eq 2229 Using ...View the full answer

Engineering Mechanics Statics & Dynamics

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