The velocity of a particle traveling along a straight line is v = (3t- 6t) ft/s, where

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The velocity of a particle traveling along a straight line is v = (3t²- 6t) ft/s, where t is in seconds. If s = 4 ft when t = 0, determine the position of the particle when t = 4 s. What is the total distance traveled during the time interval t = 0 tot = 4 s? Also, what is the acceleration when t = 2 s?

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