In a simple reaction A ↔ A*, a molecule is interconvertible between two forms that differ in standard free energy G° by 18 kJ/mole, with A* having the higher G°.

A. Use Table 3–1 to find how many more molecules will be in state A* compared with state A at equilibrium. 

B. If an enzyme lowered the activation energy of the reaction by 11.7 kJ/mole, how would the ratio of A to A* change?

Transcribed Image Text:

TABLE 3-1 RELATIONSHIP BETWEEN THE STANDARD FREE- ENERGY CHANGE, AG°, AND THE EQUILIBRIUM CONSTANT Equilibrium Constant [X]/[M] 105 104 103 10² 10 1 10-1 10-² 10-3 10-4 10-5 Standard Free-Energy Change (AG) for Reaction Y→ X (kJ/mole) -29.7 -23.8 -17.8 -11.9 -5.9 0 5.9 11.9 17.8 23.8 29.7