The solution to the Schrdinger equation for a particular potential is 0 for x a and A sin(x a) for a x a, where A and a are constants In terms of a, what value of A is required to normalize ...

Given wave Equation AScn f31a x a Here A and ...

The solution to the Schrdinger equation for a particular potential is = 0 for |x| >

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The solution to the Schrödinger equation for a particular potential is ψ = 0 for |x| > a and ψ = A sin(πx/a) for -a ≤x ≤a, where A and a are constants. In terms of a, what value of A is required to normalize ψ?

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The solution to the Schrdinger equation for a particular potential is = 0 for |x| >

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