A curve is such that dy/dx = kx 5 where k is a constant. The gradient

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A curve is such that dy/dx = kx – 5 where k is a constant.

The gradient of the normal to the curve at the point (2, -1) is – 1/3. Find the equation of the curve.

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Cambridge IGCSE And O Level Additional Mathematics Coursebook

ISBN: 9781108411660

2nd Edition

Authors: Sue Pemberton

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Question Posted: Sep 06, 2021 01:20 AM

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A curve is such that dy/dx = kx 5 where k is a constant. The gradient

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Since the gradient of the normal to the curve at the point 2 1 is 13 the slope of ...View the full answer

Cambridge IGCSE And O Level Additional Mathematics Coursebook

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