Solve. a. log 5 (x + 8) + log 5 (x + 2) = log 5 20x
Question:
Solve.
a. log5 (x + 8) + log5 (x + 2) = log5 20x
b. log3 x + log3 (x – 2) = log3 15
c. 2 log4 x – log4 (x + 3) = 1
d. lg x + lg(x + 1) = lg 20
e. log3 x + log3(2x – 5) = 1
f. 3 + 2 log2 x = log2 (14x – 3)
g. lg(x + 5) + lg 2x = 2
h. lg x + lg(x – 15) = 2
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a log5 x 8 log5 x 2 log5 20x x 8 20xx 2 x2 2x 16 0 x 8 2 b log3 x log3 x 2 log3 15 xx ...View the full answer
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Related Book For
Cambridge IGCSE And O Level Additional Mathematics Coursebook
ISBN: 9781108411660
2nd Edition
Authors: Sue Pemberton
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