Solve the given initial-value problem. dy/dx = (3x + 2y)/(3x + 2y + 2) , y(-1) = -1

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Solve the given initial-value problem.

dy/dx = (3x + 2y)/(3x + 2y + 2) , y(-1) =  -1

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Let u 3x 2y so that dudx 3 2 dydx Then dudx 3 2uu 2 5u 6u 2 and u 25u 6 du d... View full answer

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