Calculate the pump specific speed of the pump of Prob. 14–102 at the best efficiency point for the case in which the BEP occurs at 14.0 Lpm. Provide answers in both dimensionless form and in customary U.S. units. What kind of pump is it?

Data from Prob. 14–102

Consider the pump of Prob. 14–43. The pump diameter is 1.80 cm, and it operates at ṅ = 4200 rpm. Nondimensionalize the pump performance curve, i.e., plot C_H versus C_Q. Show sample calculations of C_H and C_Q at V̇ = 14.0 Lpm.

Data from Problem 14–43

A water pump is used to pump water from one large reservoir to another large reservoir that is at a higher elevation. The free surfaces of both reservoirs are exposed to atmospheric pressure, as sketched in Fig. P14–43. The dimensions and minor loss coefficients are provided in the figure. The pump’s performance is approximated by the expression H_available = H₀ – aV̇², where shutoff head H₀ = 24.4 m of water column, coefficient a = 0.0678 m/Lpm², available pump head H_available is in units of meters of water column, and capacity V̇ is in units of liters per minute (Lpm). Estimate the capacity delivered by the pump.

Data from FIGURE P14–43

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22- = 7.85 m (elevation difference) = 2.03 cm (pipe diameter) KL. , entrance = 0.50 (pipe entrance) 22-Z1 D KL, valve KL, elbow KL, exit L Z2-21 P₁V₁=0 V₁ = 0 Reservoir = 17.5 (valve) = 0.92 (each elbow-there are 5) = 1.05 (pipe exit) = 176.5 m (total pipe length) ε = 0.25 mm (pipe roughness) E 21 Valve Pump V₂=0 Reservoir -D