As shown in the picture, two plates are filled with two kinds of unmixed liquids, the viscosity coefficient of which is liquid dynamic viscosity m 1 equals 0.14 Pa s comma 2 0.24 sm 1 equals 0.14 Pa s comma m 2 0.24 m 1 equals 0.14 Pa s comma 2 0.24 sm 1 equals 0.14 Pa s comma m 2 0.24 sm 1 equals 0.14 Pa s comma m 2 0.24 m 1 equals 0.14 Pa s comma m 2 equals 0.24 Pa s mm 1 equals 0.14 Pa s comma m 2 0.24 m 1 equals 0.14 Pa s comma 2 0.24 sm 1 equals 0.14 Pa s comma m 2 0.24 s, and the liquid thickness is delta 1 equals 0.8 mm comma 2 12 mmdelta 1 equals 0.8 mm comma delta 2 12 delta 1 equals 0.8 mm comma 2 12 mmdelta 1 equals 0.8 mm comma delta 2 12 delta 1 equals 0.8 mm comma delta 2 equals 12 mm δdelta 1 equals 0.8 mm comma delta 2 12 delta 1 equals 0.8 mm comma 2 12 mmdelta 1 equals 0.8 mm comma delta 2 12 mm, respectively. Assuming that the velocity distribution is a linear law, try to calcu-late the force required to push the upper plate with the bottom area upper A equals 0.1 normal m squared upper A equals 0.1 normal m squared upper A equals 0.1 normal m squared0.1mupper A equals 0.1 normal m squared to move at a uniform velocity of 0.4 m/s.

Transcribed Image Text:

5,-0.8mm M 5,-1.2mm u=0.4m/s