Starting with Eq. (16.35), derive the perfect gas equation of state, (p=ho R T). (This demonstrates that
Question:
Starting with Eq. (16.35), derive the perfect gas equation of state, \(p=ho R T\). (This demonstrates that the perfect gas equation of state, which historically was first obtained empirically, falls out directly from the fundamentals of statistical thermodynamics.)
\[\begin{equation*}
p=N k T\left(\frac{\partial \ln Q}{\partial V}\right)_{T} \tag{16.35}
\end{equation*}\]
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