An air bubble rises slowly through maple syrup. Three forces act on the bubble, the weight of the bubble, the buoyant force, and a "drag" force due to fluid friction between the bubble and syrup as the bubble forces the syrup out of the way to rise. The drag force is given by $F_{d r a g}=6 \pi \mu v r_{o}$ where $v$ is the velocity of the bubble and $\mu$ is the viscosity of the syrup. Assuming a $5 \mathrm{~mm}$ diameter bubble, what is the velocity of the bubble? In which direction does the drag force act? Syrup properties are:

\[\mu=1 \mathrm{Ns} / \mathrm{m}^{2} \quad ho=1250 \mathrm{~kg} / \mathrm{m}^{3}\]