The standard Gibbs energies of formation, f G, for KO 2 (s) and K 2 O(s)
Question:
The standard Gibbs energies of formation, ΔfG°, for KO2(s) and K2O(s) are -240.59 kJ mol‾1 and -322.09 kJ mol‾1, respectively, at 298 K. Calculate the equilibrium constant for the reaction below at 298 K. Is KO2(s) thermodynamically stable with respect to K2O(s) and O2(g) at 298 K?
Transcribed Image Text:
2 KO₂ (s) 3 K₂O(s) + -O₂(g) 2
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To calculate the equilibrium constant we can use the following equation G RT ln ...View the full answer
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Related Book For
General Chemistry Principles And Modern Applications
ISBN: 9780132931281
11th Edition
Authors: Ralph Petrucci, Jeffry Madura, F. Herring, Carey Bissonnette
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