The vapor pressure of Hg(l) as a function of temperature is log P(mmHg) = (0.05223 a/T) +
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The vapor pressure of Hg(l) as a function of temperature is log P(mmHg) = (–0.05223 a/T) + b, where a = 61,960 and b = 8.118; T is the Kelvin temperature. Show that at 25 °C, the concentration of Hg(g) in equilibrium with Hg(l) greatly exceeds the maximum permissible level of 0.05 mg Hg/m3 air.
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To determine whether the concentration of Hgg in equilibrium with Hgl at 25 C exceeds the maximum pe...View the full answer
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Related Book For 
General Chemistry Principles And Modern Applications
ISBN: 9780132931281
11th Edition
Authors: Ralph Petrucci, Jeffry Madura, F. Herring, Carey Bissonnette
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