A natural gas mixture consists of 88.0 mole percent CH 4 (methane) and 12.0 mole percent C
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A natural gas mixture consists of 88.0 mole percent CH4 (methane) and 12.0 mole percent C2H6 (ethane). Suppose water is saturated with the gas mixture at 20°C and 1.00 atm total pressure, and the gas is then expelled from the water by heating. What is the composition in mole fractions of the gas mixture that is expelled? The solubilities of CH4 and C2H6 at 20°C and 1.00 atm are 0.023 g/L H2O and 0.059 g/L H2O, respectively.
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Using Henrys law S 2 S 1 P 2 P 1 where P 1 100 atm ...View the full answer
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