The reaction of NbCl 4 (THF) 2 with pyridine in the presence of a reducing agent gives

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The reaction of NbCl₄(THF)₂ with pyridine in the presence of a reducing agent gives NbCl_x(py)_ywhich contains 50.02% C, 4.20% H and 11.67% N. Determine the values of x and y.

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Inorganic Chemistry

ISBN: 9781292134147

5th Edition

Authors: Catherine Housecroft

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Question Posted: Jul 22, 2023 05:46 AM

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The reaction of NbCl 4 (THF) 2 with pyridine in the presence of a reducing agent gives

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To determine the values of x and y in the compound NbClxpyy we need to calculate the molar ratios of Nb Cl py pyridine C H and N based on the given pe...View the full answer

Inorganic Chemistry

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