u1 % g=g' > 0. The reasons for the first two restrictions are obvious; the third is

u½ð1 % gÞ=g' > 0.

The reasons for the first two restrictions are obvious; the third is required so that U0 > 0.

a. Calculate r(W ) for this function. Show that the reciprocal of this expression is linear in W. This is the origin of the term harmonic in the function’s name.

b. Show that when m ¼ 0 and y ¼ [(1 % g)/g] g%1

, this function reduces to the CRRA function given in Chapter 7 (see footnote 17).

c. Use your result from part

(a) to show that if g fi 1, then r(W ) is a constant for this function.

d. Let the constant found in part

(c) be represented by A. Show that the implied form for the utility function in this case is the CARA function given in Equation 7.35.

e. Finally, show that a quadratic utility function can be generated from the HARA function simply by setting g ¼ %1.

f. Despite the seeming generality of the HARA function, it still exhibits several limitations for the study of behavior in uncertain situations. Describe some of these shortcomings.