An engine turning (250 mathrm{rev} / mathrm{min}) drives a (40 mathrm{~cm}) diameter shaft with the help of
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An engine turning \(250 \mathrm{rev} / \mathrm{min}\) drives a \(40 \mathrm{~cm}\) diameter shaft with the help of belt drive system. If the diameter of engine pulleys is \(60 \mathrm{~cm}\) determine the speed of the shaft. How would the shaft speed be attached if a belt thickness of \(10 \mathrm{~mm}\) is accounted for?
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Given data Engine speed 250 mathrmrevmin Shaft diameter 40 mathrmcm Engine pulley diameter 60 mathrm...View the full answer
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