If the outermost while loop of our implementation of quickSortInPlace (line 9 of Code Fragment 12 6) were changed to use condition left right, instead of condition left Sort the subarray S a b inclusive private static void quickSortInPlace(K S, Comparator comp, int a, int b) 3 subarray is trivially sorted if (a b) return int left a 4 5 int right b 1 K pivot S b K temp while (left

Question: If the outermost while loop of our implementation of quickSortInPlace (line 9 of Code Fragment 12.6) were changed to use condition left < right, instead

If the outermost while loop of our implementation of quickSortInPlace (line 9 of Code Fragment 12.6) were changed to use condition left < right, instead of condition left <= right, there would be a flaw. Explain the flaw and give a specific input sequence on which such an implementation fails.

/** Sort the subarray S[a.b] inclusive. */ private static <K> void quickSortInPlace(K[] S, Comparator<K> comp, int a, in

/** Sort the subarray S[a.b] inclusive. */ private static void quickSortInPlace(K[] S, Comparator comp, int a, int b) { 3 // subarray is trivially sorted if (a >= b) return; int left = a; 4 5 int right = b-1; K pivot = S[b]; K temp; while (left

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