Calculate the standard Gibbs free energy change and the equilibrium constant at 1 bar and (298.15 mathrm{~K})
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Calculate the standard Gibbs free energy change and the equilibrium constant at 1 bar and \(298.15 \mathrm{~K}\) for the ammonia synthesis reaction
\[ \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}(\mathrm{g})+\frac{1}{2} \mathrm{O}_{2}(\mathrm{~g}) \rightarrow \mathrm{CH}_{3} \mathrm{CHO}(\mathrm{g})+\mathrm{H}_{2} \mathrm{O}(\mathrm{g}) \]
Given that the standard free energies of formation at \(298 \mathrm{~K}\) for \(\mathrm{CH}_{3} \mathrm{CHO}\) are \(-133.978 \mathrm{~kJ} / \mathrm{mol}\) and for \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\) are \(-174.883 \mathrm{~kJ} / \mathrm{mol}\).
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