On a Mollier diagram, the slope of the curve representing a reversible isothermal process is equal to
Question:
On a Mollier diagram, the slope of the curve representing a reversible isothermal process is equal to
(a) \(T-\beta\)
(b) \(T-\frac{1}{\beta}\)
(c) \(T\)
(d) \(T+\frac{1}{\beta}\)
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