For a boost converter with switching frequency of 500 Hz, input of 50 V dc, output of 75 V dc, inductor of 2 mH, and load resistance of 2 5 , we determine the following period T 1 500 0 002 s 2 ms Vout Vin 75 50 1 (1 D), which gives D 0 333 Ton 0 333 x 2 ms 0 666 ms Toff 2 0 666 1 334 ms lout 75 2 ...

To determine the ripple voltage we need to first determine the duty cycle of the boost converter The ...

For a boost converter with switching frequency of 500 Hz, input of 50 V dc, output of

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For a boost converter with switching frequency of 500 Hz, input of 50 V dc, output of 75 V dc, inductor of 2 mH, and load resistance of 2.5 Ω, we determine the following:

period T = 1/500 = 0.002 s = 2 ms Vout/Vin = 75/50 = 1/(1-D), which gives D = 0.333 Ton = 0.333 x 2 ms =

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For a boost converter with switching frequency of 500 Hz, input of 50 V dc, output of

Question:

period T = 1/500 = 0.002 s= 2 ms Vout/Vin = 75/50 = 1/(1-D), which gives D = 0.333 Ton = 0.333 x 2 ms = 0.666 ms Toff = 2-0.666 = 1.334 ms lout = 75/2.5 = 30A in=30=(1-0.333) = 45 A = Vin Ton L=50 V x 0.666 ms + 2 mH = 16.65 A (a large ripple). A/Ripple.pk-pk

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Introduction To Electrical Power And Power Electronics

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