When oil (kinematic viscosity (1 times 10^{-4} mathrm{~m}^{2} / mathrm{s}), specific gravity 0.92) flows at a mean

Question:

When oil (kinematic viscosity \(1 \times 10^{-4} \mathrm{~m}^{2} / \mathrm{s}\), specific gravity 0.92) flows at a mean velocity of \(1.5 \mathrm{~m} / \mathrm{s}\) through a 50 -mm-diameter pipeline, the head lost in \(30 \mathrm{~m}\) of pipe is \(5.4 \mathrm{~m}\). What will be the head loss when the velocity is increased to \(3 \mathrm{~m} / \mathrm{s}\) ?

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