Refer to the green gas data on page 241 . Using the \(95 \%\) confidence interval, based on the \(t\) distribution for the mean yield

(a) decide whether or not to reject \(H_{0}: \mu=5.5 \mathrm{gal}\) in favor of \(H_{0}: \mu eq 5.5\) at \(\alpha=0.05\);

(b) decide whether or not to reject \(H_{0}: \mu=5.3 \mathrm{gal}\) in favor of \(H_{1}: \mu eq 5.3\) at \(\alpha=0.05\).

(c) Perform the \(t\) test for part

(b) to verify your conclusion.

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N Mean StDev 15 6.00933 1.07780 SE Mean 95% CI 0.27829 (5.41247, 6.60620)