Question: (a) Hunds first rule says that, consistent with the Pauli principle, the state with the highest total spin (S) will have the lowest energy. What
(a) Hund’s first rule says that, consistent with the Pauli principle, the state with the highest total spin (S) will have the lowest energy. What would this predict in the case of the excited states of helium?
(b) Hund’s second rule says that, for a given spin, the state with the highest total orbital angular momentum (L), consistent with overall antisymmetrization, will have the lowest energy. Why doesn’t carbon have L = 2?
(c) Hund’s third rule says that if a subshell (n,ℓ) is no more than half filled, then the lowest energy level has J = |L - S|; if it is more than half filled, then J = L + S has the lowest energy. Use this to resolve the boron ambiguity in Problem 5.17(b).
(d) Use Hund’s rules, together with the fact that a symmetric spin state must go with an antisymmetric position state (and vice versa) to resolve the carbon and nitrogen ambiguities in Problem 5.17(b).
Problem 5.17(b)
(b) Figure out the corresponding total angular momenta, in the notation of Equation 5.45, for the first four elements. List all the possibilities for boron, carbon, and nitrogen.
Equation 5.45
![]()
25+1 LJ. (5.45)
Step by Step Solution
3.42 Rating (158 Votes )
There are 3 Steps involved in it
a Orthohelium should have lower energy than parahelium for corresponding states which is true b Hund... View full answer
Get step-by-step solutions from verified subject matter experts
