A particle starts out (at time t = 0) in the Nth state of the infinite square
Question:
A particle starts out (at time t = 0) in the Nth state of the infinite square well. Now the “floor” of the well rises temporarily (maybe water leaks in, and then drains out again), so that the potential inside is uniform but time dependent: V0(t), with V0(0) = V0(T) = 0.
(a) Solve for the exact Cm(t), using Equation 11.116, and show that the wave function changes phase, but no transitions occur. Find the phase change, ∅(T), in terms of the function V0(t).
(b) Analyze the same problem in first-order perturbation theory, and compare your answers.
The same result holds whenever the perturbation simply adds a constant (constant in x, that is, not in t) to the potential; it has nothing to do with the infinite square well, as such. Compare Problem 1.8.
Step by Step Answer:
Introduction To Quantum Mechanics
ISBN: 9781107189638
3rd Edition
Authors: David J. Griffiths, Darrell F. Schroeter