Three isomers of C3H6O2 have the following normal boiling points: propanoic acid (CH3CH2COOH), 141C; methyl acetate (CH3COOCH3),
Question:
Three isomers of C3H6O2 have the following normal boiling points: propanoic acid (CH3CH2COOH), 141°C; methyl acetate (CH3COOCH3), 58°C; and ethyl formate (HCOOCH2CH3), 53°C. Using your understanding of intermolecular interactions, explain why
(i) propanoic acid boils at a much higher temperature than the other two and
(ii) the boiling points of methyl acetate and ethyl formate are relatively close.
Fantastic news! We've Found the answer you've been seeking!
Step by Step Answer:
Related Book For
Question Posted: