In WorkPatch 14.8, why are the rates of the forward and reverse reactions greater at the new equilibrium than at the initial equilibrium?

Data from WorkPatch 14.8

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Initial equilibrium 0.34 mol SO₂ 0.17 mol O₂ 4,0 mol SO3 Forward rate Reverse rate Add 1 mol SO₂ 4.0 mol SO3 (c) 1.34 mol SO₂ 0.17 mol O₂ 4.0 mol SO3 Equilibrium disturbed 1.34 mol SO₂ 0.17 mol O₂ 4.0 mol SO3 Forward rate Reverse rate Time passes New equilibrium ?mol SO₂ ? mol O₂ ? mol SO3 Forward rate Which is the best choice for the amounts at the new equilibrium? (a) 0.34 mol SO₂ (b) 1.04 mol SO₂ 0.17 mol O₂ 0.02 mol O₂ 4.3 mol SO3 (d) 1.68 mol SO₂ 0.02 mol O₂ 4.3 mol SO3 Reverse rate