Given that 25.0 mL of 0.170 M potassium iodide reacts completely with 0.209 M mercury(II) nitrate solution

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Given that 25.0 mL of 0.170 M potassium iodide reacts completely with 0.209 M mercury(II) nitrate solution according to the unbalanced equation: 

Hg(NO3)2(aq) + KI(aq) → HgI2(s) + KNO3(aq)

(a) What volume of Hg(NO3)2 is required for complete precipitation?

(b) What is the mass of HgI2 precipitate?

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