Seawater contains approximately 1.22 x 10 10 atoms of gold per milliliter. How many kilograms of seawater

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Seawater contains approximately 1.22 x 10¹⁰ atoms of gold per milliliter. How many kilograms of seawater must be evaporated to obtain 12.0 g of gold? (Assume the density of seawater is 1.05 g/mL.)

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Introductory Chemistry Concepts And Critical Thinking

ISBN: 9780321804907

7th Edition

Authors: Charles Corwin

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Question Posted: Dec 22, 2023 11:11 PM

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Seawater contains approximately 1.22 x 10 10 atoms of gold per milliliter. How many kilograms of seawater

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