Given that:

\(m=\) mass of the ball of the governor,

\(\omega=\) angular velocity of the governor, and

\(g=\) accelerate due to gravity, The height of Watt's governor is given by

(a) \(\frac{g}{2 \omega^{2}}\)

(b) \(\frac{g}{\omega^{2}}\)

(c) \(\frac{\sqrt{2 g}}{\omega^{2}}\)

(d) \(\frac{2 g}{\omega^{2}}\).