Consider Gregory's expansion [tan ^{-1} x=x-frac{x^{3}}{3}+frac{x^{5}}{5}-cdots=sum_{k=0}^{infty} frac{(-1)^{k}}{2 k+1} x^{2 k+1}] a. Derive Gregory's expansion using the definition
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Consider Gregory's expansion
\[\tan ^{-1} x=x-\frac{x^{3}}{3}+\frac{x^{5}}{5}-\cdots=\sum_{k=0}^{\infty} \frac{(-1)^{k}}{2 k+1} x^{2 k+1}\]
a. Derive Gregory's expansion using the definition
\[\tan ^{-1} x=\int_{0}^{x} \frac{d t}{1+t^{2}}\]
expanding the integrand in a Maclaurin series, and integrating the resulting series term by term.
b. From this result, derive Gregory's series for \(\pi\) by inserting an appropriate value for \(x\) in the series expansion for \(\tan ^{-1} x\).
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Related Book For
A Course In Mathematical Methods For Physicists
ISBN: 9781138442085
1st Edition
Authors: Russell L Herman
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