Let (u in mathcal{L}^{1}left(mathbb{R}^{n}, lambda^{n}ight)) and (epsilon>0). Show that (int u(epsilon x) d x=epsilon^{-n} int u(y) d

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Let \(u \in \mathcal{L}^{1}\left(\mathbb{R}^{n}, \lambda^{n}ight)\) and \(\epsilon>0\). Show that \(\int u(\epsilon x) d x=\epsilon^{-n} \int u(y) d y\).

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