Solve Prob. 6111 using the equation developed in Prob. 6106. Data from 6-106 For the section, I

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Solve Prob. 6€“111 using the equation developed in Prob. 6€“106.

10.5° 60 mm A 60 mm M = 15 kN-m z'- 60 mm 140 80 mm '60 mh


Data from 6-106

For the section, Iz' = 31.7(10ˆ’6) m4, Iy' = 114(10ˆ’6) m4, Iy'z' = ˆ’15.8(10ˆ’6) m4. Using the techniques outlined in Appendix A, the member€™s cross-sectional area has principal moments of inertia of Iz = 28.8(10ˆ’6) m4 and Iy = 117(10ˆ’6) m4, calculated about the principal axes of inertia y and z, respectively. If the section is subjected to the moment M = 15 kN # m, determine the stress at point A using Eq. 6€“17.

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Mechanics of Materials

ISBN: 978-0134319650

10th edition

Authors: Russell C. Hibbeler

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