A ball of mass \(m=0.200 \mathrm{~kg}\) is launched from ground level, with velocity \(v_{0}\) and an angle of elevation \(\alpha=65^{\circ}\), toward a smooth wall, perpendicular to the trajectory, which is \(d=0.90\) \(\mathrm{m}\) from the launch point. The ball impacts (almost instantaneously) the wall at a height \(h=1.60\) \(\mathrm{m}\) above the ground and bounces back with a velocity whose component parallel to the ground is \(v_{\|}^{\prime}=-2.50 \mathrm{~m} / \mathrm{s}\). Calculate:

1. the initial velocity \(v_{0}\) of the ball;

2. the impulse \(J\) exerted on the ball by the wall;

3. the kinetic energy \(K_{s}\) of the ball when it falls back to the ground;

4. the energy dissipated in the impact.