Prove that (x + y)/(x 2 + 2y 2 + 6) has a maximum at (2, 1)
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Prove that (x + y)/(x2 + 2y2 + 6) has a maximum at (2, 1) and a minimum at (–2, –1).
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x y fx yx2y 6 Now fx 2yx2xy 6 x2y 6 x2y4xy6 x2y 6 and sofhas stationary val...View the full answer
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